Integrand size = 23, antiderivative size = 121 \[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\frac {4 x \left (c+d x^3\right )^{11/12}}{15 a \left (a+b x^3\right )^{5/4}}+\frac {11 x \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{5/4} \left (c+d x^3\right )^{11/12} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {5}{4},\frac {4}{3},-\frac {(b c-a d) x^3}{a \left (c+d x^3\right )}\right )}{15 a \left (a+b x^3\right )^{5/4}} \]
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Time = 0.04 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {386, 388} \[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\frac {11 x \left (c+d x^3\right )^{11/12} \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{5/4} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {5}{4},\frac {4}{3},-\frac {(b c-a d) x^3}{a \left (d x^3+c\right )}\right )}{15 a \left (a+b x^3\right )^{5/4}}+\frac {4 x \left (c+d x^3\right )^{11/12}}{15 a \left (a+b x^3\right )^{5/4}} \]
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Rule 386
Rule 388
Rubi steps \begin{align*} \text {integral}& = \frac {4 x \left (c+d x^3\right )^{11/12}}{15 a \left (a+b x^3\right )^{5/4}}+\frac {(11 c) \int \frac {1}{\left (a+b x^3\right )^{5/4} \sqrt [12]{c+d x^3}} \, dx}{15 a} \\ & = \frac {4 x \left (c+d x^3\right )^{11/12}}{15 a \left (a+b x^3\right )^{5/4}}+\frac {11 x \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{5/4} \left (c+d x^3\right )^{11/12} \, _2F_1\left (\frac {1}{3},\frac {5}{4};\frac {4}{3};-\frac {(b c-a d) x^3}{a \left (c+d x^3\right )}\right )}{15 a \left (a+b x^3\right )^{5/4}} \\ \end{align*}
Time = 5.68 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.74 \[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\frac {x \sqrt [4]{1+\frac {b x^3}{a}} \left (c+d x^3\right )^{11/12} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {9}{4},\frac {4}{3},\frac {(-b c+a d) x^3}{a \left (c+d x^3\right )}\right )}{a^2 \sqrt [4]{a+b x^3} \left (1+\frac {d x^3}{c}\right )^{5/4}} \]
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\[\int \frac {\left (d \,x^{3}+c \right )^{\frac {11}{12}}}{\left (b \,x^{3}+a \right )^{\frac {9}{4}}}d x\]
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\[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\int { \frac {{\left (d x^{3} + c\right )}^{\frac {11}{12}}}{{\left (b x^{3} + a\right )}^{\frac {9}{4}}} \,d x } \]
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Timed out. \[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\int { \frac {{\left (d x^{3} + c\right )}^{\frac {11}{12}}}{{\left (b x^{3} + a\right )}^{\frac {9}{4}}} \,d x } \]
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\[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\int { \frac {{\left (d x^{3} + c\right )}^{\frac {11}{12}}}{{\left (b x^{3} + a\right )}^{\frac {9}{4}}} \,d x } \]
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Timed out. \[ \int \frac {\left (c+d x^3\right )^{11/12}}{\left (a+b x^3\right )^{9/4}} \, dx=\int \frac {{\left (d\,x^3+c\right )}^{11/12}}{{\left (b\,x^3+a\right )}^{9/4}} \,d x \]
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